hdu 1102 A + B Problem II (java大数)
2014-12-15 19:38
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A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 230178 Accepted Submission(s): 44173
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should
not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the
equation. Output a blank line between two test cases.
Sample Input
2 1 2 112233445566778899 998877665544332211
Sample Output
Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110 代码一:import java.util.*; import java.math.*; public class Main { public static void main(String args[]) { Scanner cin=new Scanner(System.in); int t; int i; BigInteger a,b; t=cin.nextInt(); for(i=1;i<=t;i++) { a=cin.nextBigInteger(); b=cin.nextBigInteger(); System.out.println("Case "+i+":"); System.out.println(a+" + "+b+" = "+a.add(b)); if(i!=t) { System.out.println(); } } } }
A了,但神奇的是代码二PE,还求大神指点迷津
代码二:[code]import java.util.*;
import java.math.*;
public class Main
{
public static void main(String args[])
{
Scanner cin=new Scanner(System.in);
int t;
int i;
BigInteger a,b,s;
t=cin.nextInt();
for(i=1;i<=t;i++)
{
a=cin.nextBigInteger();
b=cin.nextBigInteger();
s=a.add(b);
if(i==t)
{
System.out.println("Case "+i+":");
System.out.println(a+" + "+b+" = "+s);
}
else
{
System.out.println("Case "+i+":");
System.out.println(a+" + "+b+" = "+s+"\n");
}
}
}
}
[/code]
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