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复数计算

2014-12-14 12:20 239 查看
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
//(1)设计复数类Complex,计算两个复数之和、差,同时以 a+bi 的字符串形式显示。
//(2)使用复数类Complex验证两个复数 1+2i 和3+4i 相加产生一个新的复数 4+6i ,相减产生一个新的复数 -2-2i
namespace 复数类
{
class Program
{
static void Main(string[] args)
{
double number1, number2, number3, number4,x,y;
Console.WriteLine("请输入第一复数的a:");
number1 = double.Parse(Console.ReadLine());
Console.WriteLine("请输入第一复数的b:");
number2 = double.Parse(Console.ReadLine());
Console.WriteLine("请输入第二复数的a:");
number3 = double.Parse(Console.ReadLine());
Console.WriteLine("请输入第二复数的b:");
number4 = double.Parse(Console.ReadLine());
Complex nub = new Complex();
x = nub.Add(number1, number3);
y = nub.Add(number2, number4);
Console.WriteLine("{0}+{1}i与{2}+{3}i相加的结果为:{4}+{5}i", number1, number2, number3, number4, nub.Add(number1, number3), nub.Add(number2, number4));
if (nub.Subtract(number2, number4)<0)
Console.WriteLine("{0}+{1}i与{2}+{3}i相减的结果为:{4}{5}i", number1, number2, number3, number4, nub.Subtract(number1, number3), nub.Subtract(number2, number4));
else Console.WriteLine("{0}+{1}i与{2}+{3}i相减的结果为:{4}{5}i", number1, number2, number3, number4, nub.Subtract(number1, number3), nub.Subtract(number2, number4));

Console.ReadLine();
}
}
class Complex
{

public double Add(double a, double b)
{
return a + b;

}
public double Subtract(double a, double b)
{

return a - b;

}

}
}




总结:好难!
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