BZOJ3732 Network
2014-12-13 10:02
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这貌似是13年的noip最后一道吧?、、、
蒟蒻只会这种题呢、、、
Kruskal求出MST,然后倍增就好了
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蒟蒻只会这种题呢、、、
Kruskal求出MST,然后倍增就好了
/************************************************************** Problem: 3732 User: rausen Language: C++ Result: Accepted Time:268 ms Memory:4412 kb ****************************************************************/ #include <cstdio> #include <algorithm> using namespace std; const int N = 16005; const int M = 30005; struct Edge { int x, y, v; inline bool operator < (const Edge &x) const { return v < x.v; } } E[M]; struct edge { int next, to, v; edge() {} edge(int _n, int _t, int _v) : next(_n), to(_t), v(_v) {} } e[M]; struct tree_node { int fa[16], mx[16], dep; } tr ; int n, m; int fa ; int tot, first ; inline int read() { int x = 0; char ch = getchar(); while (ch < '0' || '9' < ch) ch = getchar(); while ('0' <= ch && ch <= '9') { x = x * 10 + ch - '0'; ch = getchar(); } return x; } inline void Add_Edges(int x, int y, int v) { e[++tot] = edge(first[x], y, v), first[x] = tot; e[++tot] = edge(first[y], x, v), first[y] = tot; } int find_fa(int x) { return x == fa[x] ? x : fa[x] = find_fa(fa[x]); } void Kruskal() { int i, cnt, fa1, fa2; sort(E + 1, E + m + 1); for (i = 1; i <= n; ++i) fa[i] = i; for (i = 1, cnt = 0; i <= m; ++i) { fa1 = find_fa(E[i].x), fa2 = find_fa(E[i].y); if (fa1 != fa2) { fa[fa1] = fa2, ++cnt; Add_Edges(E[i].x, E[i].y, E[i].v); if (cnt == n - 1) break; } } } void dfs(int p) { int x, y; for (x = 1; x < 16; ++x) { tr[p].fa[x] = tr[tr[p].fa[x - 1]].fa[x - 1]; tr[p].mx[x] = max(tr[p].mx[x - 1], tr[tr[p].fa[x - 1]].mx[x - 1]); } for (x = first[p]; x; x = e[x].next) if ((y = e[x].to) != tr[p].fa[0]) { tr[y].dep = tr[p].dep + 1; tr[y].fa[0] = p, tr[y].mx[0] = e[x].v; dfs(y); } } int query(int x, int y) { int res = 0, i; if (tr[x].dep < tr[y].dep) swap(x, y); for (i = 15; ~i; --i) if (tr[tr[x].fa[i]].dep >= tr[y].dep) { res = max(res, tr[x].mx[i]); x = tr[x].fa[i]; } for (i = 15; ~i; --i) if (tr[x].fa[i] != tr[y].fa[i]) { res = max(res, max(tr[x].mx[i], tr[y].mx[i])); x = tr[x].fa[i], y = tr[y].fa[i]; } if (x != y) res = max(res, max(tr[x].mx[0], tr[y].mx[0])); return res; } int main() { n = read(), m = read(); int Q = read(), i, x, y; for (i = 1; i <= m; ++i) E[i].x = read(), E[i].y = read(), E[i].v = read(); Kruskal(); tr[1].dep = 1; dfs(1); while (Q--) { x = read(), y = read(); printf("%d\n", query(x, y)); } return 0; }
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