您的位置:首页 > 其它

Longest Substring Without Repeating Characters

2014-12-11 20:25 211 查看
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without
repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1.

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
//时间复杂度为O(n^3),超时了
int llenthOfLongestSubstring(char *s)
{
int len=strlen(s);
int i,j,k,flag;
int sum=1,max=0;
for(i=0;i<len;i++){
for(j=i+1,k=j;j<len;j++){
//printf("i-%d,j-%d\n",i,j);
for(k=i,flag=1;k<j;k++){
if(s[j]!=s[k]) flag=1;
else {
flag=0;
break;
}
}
if(flag==1) sum++;
else break;
}
if(sum>max) max=sum;
sum=1;
i=k;
}
return max;
}
//时间复杂度为O(n),通过
int lenthOfLongestSubstring(char *s){
int len=strlen(s);
int ht[256];
int i,curlen;
int start=0,max=0;
for(i=0;i<256;i++) ht[i]=-1;
for(i=0;i<len;i++){
if(start>ht[s[i]]) ht[s[i]]=i;
else{
curlen=i-start;
if(curlen>max){
max=curlen;
}
start=ht[s[i]]+1;
ht[s[i]]=i;
}
}
curlen=i-start;
if(curlen>max) max=curlen;
if(max==0) return len;
return max;
}

void main(){
printf("%d\n",lenthOfLongestSubstring("msboaguwnnyqxnzlgdgwpbtrwblnsadeuguumoqcdrubetokyxhoachwdvmxxrdryxlmndqtukwagmlejuu"));
printf("%d\n",lenthOfLongestSubstring("wlrbbmqbhcdarzowkkyhiddqscdxrjmowfrxsjybldbefsarcbynecdyggxxpklorellnmpapqfwkhopkmco"));
printf("%d\n",lenthOfLongestSubstring("qopubjguxhxdipfzwswybgfylqvjzhar"));
printf("%d\n",llenthOfLongestSubstring("qopubjguxhxdipfzwswybgfylqvjzhar"));
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: