用递归函数计算厄密多项式

int hermite( int n, int x );

/*
** 计算Hermite Polynomials(厄密多项式)的值
*/

#include <stdio.h>

int hermite( int n, int x );

int
main()
{
int n, x;
scanf( "%d%d", &n, &x );
printf( "%d", hermite( n, x ) );
return 0;
}

/*
** 计算厄密多项式的值，递归函数版本
*/
int
hermite( int n, int x )
{
int result;

if( n <= 0 )
result = 1;
else {
if( n == 1 )
result = 2 * x;
else
result = 2 * x * hermite( n - 1, x )
- 2 * ( n - 1 ) * hermite( n - 2, x );
}
return result;
}