C 语言程序设计实践 7.6 函数计算

#include <stdio.h>
int fun1(int b);
int fun2(int b);
int fun3(int b);
int fun4(int b);
int fun5(int b);
int fun6(int b);
int main()
{
int n,a,b,c;
scanf("%d",&n);
while (n--){
scanf("%d %d",&a,&b);
if (a==1)
c=fun1(b);
else if (a==2)
c=fun2(b);
else if (a==3)
c=fun3(b);
else if (a==4)
c=fun4(b);
else if (a==5)
c=fun5(b);
else
c=fun6(b);
printf("%d\n",c);
}
return 0;
}

int fun1(int b)
{
return (b+56);
}

int fun2(int b)
{
return (b-32);
}

int fun3(int b)
{
return (2*b);
}

int fun4(int b)
{
return (fun3(fun1(b)));
}

int fun5(int b)
{
return (fun2(fun3(b)));
}

int fun6(int b)
{
return (fun5(fun4(b)));
}