poj 1004 Financial Management

这道题目读到最后就是个求平均数的问题，这真的是一道水到极点的题目，本来以为会在数字表达上面有些难度，于是写了个round，然后两次compile error，系统不识别round函数，可是这在我的vs上面能跑的，没办法写了一个myround实现数据元整，后来发现完全没有必要，AC之后看了其他孩子的代码，压根就没数据后两位的处理，果然还是我想多了，水题，不推荐做。突然发现自己已经习惯拿到一个问题直接写一个类了，明明想用C来写的，不知道该高兴呢，还是该桑心呢


Source Code

Problem: 1004		User: zhyh2010
Memory: 220K		Time: 0MS
Language: C++		Result: Accepted

Source Code

#include <iostream>
#include <cmath>
//#include <iomanip>

using namespace std;

class MEAN
{
public:
MEAN();
~MEAN();

void input();
void output();
void algorithm();

protected:
int myround(float key);

private:
static const int MM = 12;

float m_data[MM];
float m_aver;
};

MEAN::MEAN()
{
/*m_data[0] = 100.00;
m_data[1] = 489.12;
m_data[2] = 12454.12;
m_data[3] = 1234.10;
m_data[4] = 823.05;
m_data[5] = 109.20;
m_data[6] = 5.27;
m_data[7] = 1542.25;
m_data[8] = 839.18;
m_data[9] = 83.99;
m_data[10] = 1295.01;
m_data[11] = 1.75;*/

m_aver = 0;
}

MEAN::~MEAN()
{

}

void MEAN::input()
{
for (int i = 0; i != MM; ++i)
{
cin >> m_data[i];
}
}

void MEAN::output()
{
cout << "$"<<m_aver << endl;
}

void MEAN::algorithm()
{
float sum = 0;
for (int i = 0; i != MM; ++i)
{
sum += m_data[i];
}
m_aver = sum / MM;

int temp;
temp = myround(m_aver * 100);
m_aver = temp / 100.0;
}

int MEAN::myround(float key)
{
return floor(key + 0.5);
}

int main(int argc,char ** argv)
{
MEAN instance;
instance.input();
instance.algorithm();
instance.output();

return 0;
}