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LeetCode:Single Number

2014-11-29 13:26 239 查看
Given an array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

class Solution {
public:
int singleNumber(int A[], int n) {
int i;
for (i = 1; i < n; i++) {
A[0] ^= A[i];
}
return A[0];
}
};
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