递归方法实现多种进制的转换

#include<iostream>

#include<string>

using namespace std;

//进制转换

void convto(char *s,int n,int b)

{

char bit[]=("0123456789ABCDEF");

int len;

if(n==0)

{

strcpy(s,"");

return ;

}

convto(s,n/b,b);

len=strlen(s);//只算有效的字符长度

s[len]=bit[n%b];

s[len+1]='\0';

}

int main(void)

{

char s[100];

int i,base,old;

cout<<"请输入十进制数："<<endl;

cin>>old;

cout<<"请输入转换的进制："<<endl;

cin>>base;

convto(s,old,base);

cout<<s<<endl;

return 0;

}