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【LeetCode】Rotate List

2014-11-18 19:07 387 查看
把倒数k个节点放到开始节点的前面,注意 n可能很大,需要对长度取余。

/**
* Definition for singly-linked list.
* public class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) {
*         val = x;
*         next = null;
*     }
* }
*/
public class Solution {
public ListNode rotateRight(ListNode head, int n) {
if(head == null || head.next == null)return head;
int count = 0;
int cur = 0;
ListNode dummy = new ListNode(0);
dummy.next = head;
ListNode p = head;
ListNode pre = head;
while(p != null){
count++;
p = p.next;
}
n = n % count;
if(n == 0) return head;
p = head;
while(p != null){
cur++;
pre = p;
p = p.next;
if(cur == count - n) break;
}
pre.next = null;
ListNode newHead = p;
while(p != null){
pre = p;
p = p.next;
}
pre.next = dummy.next;
return newHead;
}
}
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