[LeetCode] Remove Duplicates from Sorted Array
2014-11-11 10:55
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Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place and constant memory.
For example,
Given input array A= [1, 1, 2],
Your function should return length = 2, and A is now [1, 2].
Ideas: Put the unequal element into the same array
class Solution {
public:
int removeDuplicates(int A[], int n) {
if(n <= 1) return n;
int j = 0;
for(int i = 1; i < n; i++)
{
if(A[j] != A[i])
{
A[++j] = A[i];
}
}
return j + 1;
}
};
Do not allocate extra space for another array, you must do this in place and constant memory.
For example,
Given input array A= [1, 1, 2],
Your function should return length = 2, and A is now [1, 2].
Ideas: Put the unequal element into the same array
class Solution {
public:
int removeDuplicates(int A[], int n) {
if(n <= 1) return n;
int j = 0;
for(int i = 1; i < n; i++)
{
if(A[j] != A[i])
{
A[++j] = A[i];
}
}
return j + 1;
}
};
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