【Leetcode】Gray Code (Pascal)
2014-11-10 00:03
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The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
is:
Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
八字口诀就可以把这道题解决
左移加数,倒序相加
意思是把1左移0~n-1位然后和原数组记录的所有数倒序相加就能得到结果了
public static ArrayList<Integer> grayCode(int n) {
ArrayList<Integer> result = new ArrayList<Integer>();
result.add(0);
for (int i = 0; i < n; i++) {
int inc = 1 << i;
for (int j = result.size() - 1; j >= 0; j--) {
result.add(result.get(j) + inc);
}
}
return result;
}
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
[0,1,3,2]. Its gray code sequence
is:
00 - 0 01 - 1 11 - 3 10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
[0,2,3,1]is also a valid gray code sequence according to the above definition.
八字口诀就可以把这道题解决
左移加数,倒序相加
意思是把1左移0~n-1位然后和原数组记录的所有数倒序相加就能得到结果了
public static ArrayList<Integer> grayCode(int n) {
ArrayList<Integer> result = new ArrayList<Integer>();
result.add(0);
for (int i = 0; i < n; i++) {
int inc = 1 << i;
for (int j = result.size() - 1; j >= 0; j--) {
result.add(result.get(j) + inc);
}
}
return result;
}
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