HDU'14’11'校赛 Harmonious Contest

#include<stdio.h>
int main()
{
int a,b,c,n,i,t;
while(~scanf("%d",&n))
{

for(i=1;i<=n;i++)
{
scanf("%d%d%d",&a,&b,&c);
if(a>b&&a>c)
{t=a;a=c;c=t;}
else if(b>a&&b>c)
{t=b;b=c;c=t;}
if(a+b<=c||a-b>=c)printf("NO\n");
else if(a*a+b*b==c*c||a*a==b*b+c*c||a*a+c*c==b*b)printf("Right triangle\n");
else if(a*a+b*b>c*c)printf("Acute triangle\n");
else if(a*a+b*b<c*c)printf("Obtuse triangle\n");
}
}
return 0;
}

Harmonious Contest

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 0 Accepted Submission(s): 0


[align=left]Problem Description[/align]

This is a magic country
Harmonious society
And harmonious people

This is a wonderful contest
Harmonious students
And harmonious problems.

This is the most harmonious problem, and the question is as following:
Given three positive integers A, B and C (0<A,B,C<=100) which denote the length of three edges, please tell me whether they can make up a legal triangle.

[align=left]Input[/align]

The first line is an integer T(T<=100) which indicates the number of test cases.
Each test case consists of three integers A,B and C in a line.

[align=left]Output[/align]

For each test case please output the type of triangle (Acute triangle、Right triangle or Obtuse triangle) if A,B and C can make up a legal triangle, and output "NO" otherwise.
One line per case.

[align=left]Sample Input[/align]

4
3 4 4
3 4 5
3 4 6
3 4 7

[align=left]Sample Output[/align]

Acute triangle
Right triangle
Obtuse triangle
NO