PAT 1058 A+B in Hogwarts
2014-11-04 00:09
239 查看
#include <cstdio> #include <cstdlib> using namespace std; class Number { public: int a; int b; int c; Number(int _a = 0, int _b = 0, int _c = 0): a(_a), b(_b), c(_c){} Number operator+(const Number& n) { Number tmp; tmp.a = a + n.a; tmp.b = tmp.a / 29; tmp.a = tmp.a % 29; tmp.b += b + n.b; tmp.c = tmp.b / 17; tmp.b = tmp.b % 17; tmp.c += c + n.c; tmp.c = tmp.c; return tmp; } void print() { printf("%d.%d.%d", c, b, a); } }; int main() { Number n1, n2; scanf("%d.%d.%d", &n1.c, &n1.b, &n1.a); scanf("%d.%d.%d", &n2.c, &n2.b, &n2.a); Number n3 = n1 + n2; n3.print(); return 0; }
感觉是个坑,明明说了Galleon is an integer in [0, 107],结果tmp.c不用取模就对了,麻烦把定义说明白一些
相关文章推荐
- PAT (Advanced) 1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)
- PAT甲级1058. A+B in Hogwarts (20)
- PAT1058:A+B in Hogwarts
- 浙江大学PAT_甲级_1058. A+B in Hogwarts (20)
- 【PAT (Advanced Level)】1058. A+B in Hogwarts (20)
- PAT 甲级 1058. A+B in Hogwarts (20)
- 【PAT】1058. A+B in Hogwarts
- PAT (Advanced Level) 1058. A+B in Hogwarts (20)
- PAT-1058 A+B in Hogwarts (进制转换)
- PAT (Advanced Level) Practise 1058 A+B in Hogwarts (20)
- pat甲级1058. A+B in Hogwarts (20)
- PAT (Advanced Level) Practise 1058 A+B in Hogwarts (20)
- zju pat 1058 A+B in Hogwarts
- PAT 1058. A+B in Hogwarts (20)
- 【c++】PAT(advanced level)1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts
- 【PAT】【Advanced Level】1058. A+B in Hogwarts (20)
- 1058. A+B in Hogwarts (20)-PAT甲级真题
- PAT程序设计考题——甲级1058(A+B in Hogwarts ) C++实现