SQL查询按指定字段排序

city_name是字段名，现在要按("北京","上海","广州")   先后顺序把数据查询统计出来？

不知道你什么数据库, 假如是 Oracle:

select
count(city_name),
city_name
from
tuan_info
where
source_type  = 1
and  city_name in("北京","上海","广州")
group    by
city_name
ORDER BY
INSTR('北京,上海,广州', city_name);

如果是 SQL Server 用
ORDER BY CHARINDEX(city_name, '北京,上海,广州')

是SQL Server 的，怎么写哦，给个完整点的语句好吗

select
count(city_name),
city_name
from
tuan_info
where
source_type  = 1
and  city_name in("北京","上海","广州")
group    by
city_name
ORDER BY CHARINDEX(city_name, '北京,上海,广州')

前面的SQL都是一样的啊。
只是 增加一个  ORDER BY 的排序处理。

在吗，不行的，提示有错啊，是什么问题哦
[SQL] select count(city_name), city_name from tuan_info where source_type  = 1 and  city_name in("北京","上海","广州") group by city_name ORDER BY CHARINDEX(city_name, '北京,上海,广州');
[Err] 1305 - FUNCTION data_group.CHARINDEX does not exist

你这个是什么数据库啊？

CHARINDEX  是 SQL Server 自带的函数啊。

那个，，是MYSQL的哦，怎办

MySQL  就换一个函数   INSTR

select
count(city_name),
city_name
from
tuan_info
where
source_type  = 1
and  city_name in("北京","上海","广州")
group    by
city_name
ORDER BY INSTR( '北京,上海,广州',   city_name)