An easy problem

[align=left]Problem Description[/align]
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

[align=left]Input[/align]
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

[align=left]Output[/align]
for each case, you should the result of y+f(x) on a line.

[align=left]Sample Input[/align]

6

R 1

P 2

G 3

r 1

p 2

g 3

[align=left]Sample Output[/align]

19
18

10

-17

-14

-4

#include <stdio.h>
#include <ctype.h>

int main(){
int T;
char c;
int number;
int result;

scanf("%d",&T);

while(T--){
getchar();
scanf("%c%d",&c,&number);

if(islower(c)!=0){
result=c-'a'+1;
result=-result;
result+=number;
}

else{
result=c-'A'+1;
result+=number;
}

printf("%d\n",result);
}

return 0;
}