UVa 1339 - Ancient Cipher
2014-10-21 13:06
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也是书上的例题,书上只给出了个函数,可是我怎么看都看不懂那个函数怎么用,还是得自己写,自己写的没用函数。。。我觉得没必要用吧。
#include<string.h> #include<stdio.h> int cnt1[26]= {0},cnt2[26]= {0}; char str1[110],str2[110]; int main() { int i,j,n,n1,n2; while(scanf("%s%s",str1,str2)!=EOF) { int count=0; memset(cnt1,0,sizeof(cnt1)); memset(cnt2,0,sizeof(cnt2)); n=strlen(str1); for(i=0; i<n; i++) { cnt1[str1[i]-'A']++; cnt2[str2[i]-'A']++; } for(i=0; i<26; i++) { for(j=0; j<26; j++) { if(cnt1[i]==cnt2[j]&&cnt1[i]!=0&&cnt2[j]!=0) {count+=cnt2[j]; cnt2[j]=0; break;} } } if(count==n) printf("YES\n"); else printf("NO\n"); } return 0; }
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