leetcode:Symmetric Tree【Python版】
2014-10-18 21:33
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#error caused by:
#1:{} 没有考虑None输入
#2:{1,2,2} 没有控制h和t
#3:{4,-57,-57,#,67,67,#,#,-97,-97} 没有考虑负号,将s从str变成list,采用9999代表空数值;
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逐层进行对称性验证,出现不对称就结束;
#1:{} 没有考虑None输入
#2:{1,2,2} 没有控制h和t
#3:{4,-57,-57,#,67,67,#,#,-97,-97} 没有考虑负号,将s从str变成list,采用9999代表空数值;
---------------------
逐层进行对称性验证,出现不对称就结束;
# Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: # @param root, a tree node # @return a boolean def isSymmetric(self,root): ret = True q = [] s = [] if root != None:#注意root为空 q.append(root) s.append(root.val) while (len(q) != 0 and ret == True): h = 0 t = len(s) - 1 while (h < t): if (s[h] != s[t]): ret = False break h+=1#这里忘记控制h和t了 t-=1 tq = q s = [] q = [] while (len(tq) != 0 and ret == True): t = tq.pop(0)#pop默认弹出最后一个值 if t.left != None: q.append(t.left) s.append(t.left.val) else: s.append(9999) if t.right != None: q.append(t.right) s.append(t.right.val) else: s.append(9999) return ret
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