POJ 3094 Quicksum(简单题)

// 200K 0Ms
#include<iostream>
using namespace std;

int main()
{
char a[256];
while(1)
{
int sum = 0;
gets(a);
if(strcmp(a,"#")==0) break;
int len = strlen(a);
for(int i = 0;i<len;i++)
{
if(a[i] == ' ')
sum += 0;
else
sum += (a[i]-'A'+1)*(i+1);
}
cout<<sum<<endl;
}
return 0;
}