poj 1611
2014-10-18 08:54
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The Suspects
Description
Severe acuterespiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, wasrecognized as a global threat in mid-March 2003. To minimize transmission toothers, the best strategy is to separate the suspects from others.
In the Not-Spreading-Your-Sickness University (NSYSU), there are many studentgroups. Students in the same group intercommunicate with each other frequently,and a student may join several groups. To prevent the possible transmissions ofSARS, the NSYSU collects
the member lists of all student groups, and makes thefollowing rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a studentis recognized as a suspect. Your job is to write a program which finds all thesuspects.
Input
The input filecontains several cases. Each test case begins with two integers n and m in aline, where n is the number of students, and m is the number of groups. You mayassume that 0 < n <= 30000 and 0 <= m <= 500. Every student isnumbered by
a unique integer between 0 and n−1, and initially student 0 isrecognized as a suspect in all the cases. This line is followed by m memberlists of the groups, one line per group. Each line begins with an integer k byitself representing the number of members
in the group. Following the number ofmembers, there are k integers representing the students in this group. All theintegers in a line are separated by at least one space.
A case with n = 0 and m = 0 indicates the end of the input, and need not beprocessed.
Output
For each case,output the number of suspects in one line.
Sample Input
100 4
2 1 2
5 10 13 11 12 14
2 0 1
2 99 2
200 2
1 5
5 1 2 3 4 5
1 0
0 0
Sample Output
4
1
1
很简单的并查集,代码如下:
#include<stdio.h>
int set[30001];
int a[30001];
int find(int x)
{
intr=x;
while(set[r]!=r)
r=set[r];
returnr;
}
void merge(int a,int b)
{
if(a<b)
set[b]=a;
else
set[a]=b;
}
int main()
{
intn,m,k,i,j,p,q,x;
while(scanf("%d%d",&n,&m)&&(n!=0||m!=0))
{
intcount=0;
for(i=0;i<n;i++)
set[i]=i;
for(i=0;i<m;i++)
{
scanf("%d",&k);
for(j=0;j<k;j++)
scanf("%d",&a[j]);
for(j=0;j<k-1;j++)
{
p=find(a[j]);
q=find(a[j+1]);
merge(p,q);
}
}
q=find(0);
for(i=0;i<n;i++)
{
p=find(i);
if(p==q)
count++;
}
printf("%d\n",count);
}
return0;
}
Time Limit: 1000MS | Memory Limit: 20000K |
Total Submissions: 23099 | Accepted: 11217 |
Severe acuterespiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, wasrecognized as a global threat in mid-March 2003. To minimize transmission toothers, the best strategy is to separate the suspects from others.
In the Not-Spreading-Your-Sickness University (NSYSU), there are many studentgroups. Students in the same group intercommunicate with each other frequently,and a student may join several groups. To prevent the possible transmissions ofSARS, the NSYSU collects
the member lists of all student groups, and makes thefollowing rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a studentis recognized as a suspect. Your job is to write a program which finds all thesuspects.
Input
The input filecontains several cases. Each test case begins with two integers n and m in aline, where n is the number of students, and m is the number of groups. You mayassume that 0 < n <= 30000 and 0 <= m <= 500. Every student isnumbered by
a unique integer between 0 and n−1, and initially student 0 isrecognized as a suspect in all the cases. This line is followed by m memberlists of the groups, one line per group. Each line begins with an integer k byitself representing the number of members
in the group. Following the number ofmembers, there are k integers representing the students in this group. All theintegers in a line are separated by at least one space.
A case with n = 0 and m = 0 indicates the end of the input, and need not beprocessed.
Output
For each case,output the number of suspects in one line.
Sample Input
100 4
2 1 2
5 10 13 11 12 14
2 0 1
2 99 2
200 2
1 5
5 1 2 3 4 5
1 0
0 0
Sample Output
4
1
1
很简单的并查集,代码如下:
#include<stdio.h>
int set[30001];
int a[30001];
int find(int x)
{
intr=x;
while(set[r]!=r)
r=set[r];
returnr;
}
void merge(int a,int b)
{
if(a<b)
set[b]=a;
else
set[a]=b;
}
int main()
{
intn,m,k,i,j,p,q,x;
while(scanf("%d%d",&n,&m)&&(n!=0||m!=0))
{
intcount=0;
for(i=0;i<n;i++)
set[i]=i;
for(i=0;i<m;i++)
{
scanf("%d",&k);
for(j=0;j<k;j++)
scanf("%d",&a[j]);
for(j=0;j<k-1;j++)
{
p=find(a[j]);
q=find(a[j+1]);
merge(p,q);
}
}
q=find(0);
for(i=0;i<n;i++)
{
p=find(i);
if(p==q)
count++;
}
printf("%d\n",count);
}
return0;
}
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