【LeetCode】Length of Last Word
2014-10-10 17:38
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Length of Last Word
Total Accepted: 20470 Total Submissions: 69655 My Submissions
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
【解题思路】
简单题,主要考察字符串处理基本功。
Java AC 380ms
Total Accepted: 20470 Total Submissions: 69655 My Submissions
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
【解题思路】
简单题,主要考察字符串处理基本功。
Java AC 380ms
public class Solution { public int lengthOfLastWord(String s) { s = s.trim(); String sArr[] = s.split(" "); String word = sArr[sArr.length-1].trim(); return word.length(); } }Python AC 172ms
class Solution: # @param s, a string # @return an integer def lengthOfLastWord(self, s): s = s.strip() sArr = s.split(' ') word = sArr[len(sArr)-1].strip() return len(word)
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