codeforces-#475A. Bayan Bus(模拟)
2014-10-06 09:35
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题目大意:给一个矩形的大巴乘坐规则,给定人数,输出大巴的座位的情况。
解题思路:就是字符串模拟,可以对特殊的简单处理下,这里给出两种写法,第二种写法更直接,简单粗暴。详见code。
题目大意:http://codeforces.com/problemset/problem/475/A
code:
暴力code:
解题思路:就是字符串模拟,可以对特殊的简单处理下,这里给出两种写法,第二种写法更直接,简单粗暴。详见code。
题目大意:http://codeforces.com/problemset/problem/475/A
code:
<pre name="code" class="cpp">#include <iostream> #include <cstdio> #include <cstring> using namespace std; int n,k,m; char str[4][27]={ "|#.#.#.#.#.#.#.#.#.#.#.|D|", "|#.#.#.#.#.#.#.#.#.#.#.|.|", "|#.......................|", "|#.#.#.#.#.#.#.#.#.#.#.|.|", }; int main(){ //freopen("input.txt","r",stdin); while(~scanf("%d",&k)){ if(k>34) break; printf("+------------------------+\n"); if(k<=4) for(int i=0;i<k;++i) str[i][1]='O'; else if(k>4){ for(int i=0;i<4;++i) str[i][1]='O'; k-=4; n=k/3; m=k%3; for(int i=0;i<4;++i) for(int j=0;j<n;++j) if(i!=2)str[i][3+2*j]='O'; for(int i=0;i<m;++i) if(i!=2)str[i][2*n+3]='O'; } for(int i=0;i<4;++i){ for(int j=0;j<26;++j) printf("%c",str[i][j]); if(i==0 || i==3)printf(")\n"); else printf("\n"); } printf("+------------------------+\n"); } return 0; }
暴力code:
#include <iostream> #include <cstdio> #include <cstring> using namespace std; int k; char str[6][30]={ "+------------------------+", "|#.#.#.#.#.#.#.#.#.#.#.|D|)", "|#.#.#.#.#.#.#.#.#.#.#.|.|", "|#.......................|", "|#.#.#.#.#.#.#.#.#.#.#.|.|)", "+------------------------+", }; int main(){ scanf("%d",&k); for(int i=0;i<30;++i) for(int j=0;j<6;++j){ if(k==0) break; if(str[j][i]=='#'){ k--; str[j][i]='O'; } } for(int i=0;i<6;++i) printf("%s\n",str[i]); return 0; }
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