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CodeForces 469A. I Wanna Be the Guy(数学)

2014-09-21 18:47 344 查看
题目链接:http://codeforces.com/contest/469/problem/A

A. I Wanna Be the Guy

time limit per test
1 second

memory limit per test
256 megabytes

input
standard input

output
standard output

There is a game called "I Wanna Be the Guy", consisting of n levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass
the whole game.

Little X can pass only p levels of the game. And Little Y can pass only q levels
of the game. You are given the indices of levels Little X can pass and the indices of levels Little Y can pass. Will Little X and Little Y pass the whole game, if they cooperate each other?

Input

The first line contains a single integer n (1 ≤  n ≤ 100).

The next line contains an integer p (0 ≤ p ≤ n) at
first, then follows p distinct integers a1, a2, ..., ap (1 ≤ ai ≤ n).
These integers denote the indices of levels Little X can pass. The next line contains the levels Little Y can pass in the same format. It's assumed that levels are numbered from 1 to n.

Output

If they can pass all the levels, print "I become the guy.". If it's impossible, print "Oh,
my keyboard!" (without the quotes).

Sample test(s)

input
4
3 1 2 3
2 2 4


output
I become the guy.


input
4
3 1 2 3
2 2 3


output
Oh, my keyboard!


Note

In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.

In the second sample, no one can pass level 4.

代码如下:

#include <cstdio>
#include <cstring>

int main()
{
    int n;
    int vis[1117];
    while(~scanf("%d",&n))
    {
        int x, y;
        memset(vis,0,sizeof(vis));
        int tt;
        scanf("%d",&x);
        for(int i = 0; i < x; i++)
        {
            scanf("%d",&tt);
            vis[tt] = 1;
        }
        scanf("%d",&y);
        for(int i = 0; i < y; i++)
        {
            scanf("%d",&tt);
            vis[tt] = 1;
        }
        int flag = 0;
        for(int i = 1; i <= n; i++)
        {
            if(vis[i] == 0)
            {
                flag = 1;
                break;
            }
        }
        if(flag)
        {
            printf("Oh, my keyboard!\n");
        }
        else
            printf("I become the guy.\n");
    }
    return 0;
}
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