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LeetCode - Single Number

2014-09-17 15:36 411 查看
Given an array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

class Solution {
public:
int singleNumber(int A[], int n) {
int num=0;
if(n<=0){
return num;
}
num=A[0];
for(int i=1;i<n;i++){
num^=A[i];
}
return num;
}
};
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