UVA - 494 Kindergarten Counting Game
2014-09-16 20:39
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题目大意:统计出每一句话有多少单词
解体思路:先把前面的非字母去掉,然后统计非字母后面接字母的数量有多少个,然后加1
解体思路:先把前面的非字母去掉,然后统计非字母后面接字母的数量有多少个,然后加1
#include<cstdio> #include<cstring> int main() { char str[300]; while(gets(str)) { int len = strlen(str); int count = 1; int begin = 0; for(;begin < len; begin++) { if(str[begin] < 'A' || (str[begin] > 'Z' && str[begin] < 'a') || str[begin] > 'z') continue; else break; } for(int i = begin; i < len; i++) { if((str[i] < 'A' || (str[i] > 'Z' && str[i] < 'a') || str[i] > 'z') && ((str[i+1] >= 'A' && str[i+1] <= 'Z') || (str[i+1] >= 'a' && str[i+1] <= 'z'))) count++; } printf("%d\n",count); } return 0; }
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