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POJ 1379 Run Away 模拟退火

2014-09-15 22:04 357 查看
一开始写了一发很快的,发现一会能过一会不能,貌似有点悬,毕竟是随机算法。

后来重写了一发迭代5遍的,基本上把把AC了= =

模拟退火果然是一种不是很靠谱的算法。

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <cstdlib>
#include <ctime>

using namespace std;
const int maxn = 1005;
const double eps = 1e-8;
const double r = 0.99;
const int dx[] = { 0, 0, 1, -1, 1, -1, 1, -1 };
const int dy[] = { 1, -1, 0, 0, 1, -1, -1, 1 };

int px[maxn], py[maxn];
int X, Y, M;

double sq(double x) {
return x * x;
}

double dis(double x, double y) {
double ret = 1e90;
for (int i = 0; i < M; i++) {
ret = min(ret, sqrt(sq(x - px[i]) + sq(y - py[i])));
}
return ret;
}

double solve(double &x, double &y) {
double nowdis = dis(x, y);
double step = max(X, Y);
while (step > eps) {
for (int i = 0; i < 8; i++) {
double nx = x + dx[i] * step,
ny = y + dy[i] * step,
ndis = dis(nx, ny);
if (nx > X || nx < 0 || ny > Y || ny < 0) continue;
if (ndis > nowdis) {
x = nx; y = ny; nowdis = ndis;
}
}
step *= r;
}
return nowdis;
}

int main() {
int T; scanf("%d", &T);
srand(time(NULL));
while (T--) {
scanf("%d%d%d", &X, &Y, &M);
for (int i = 0; i < M; i++) scanf("%d%d", &px[i], &py[i]);
double nowdis = 0, x, y;
for (int i = 0; i < 5; i++) {
double tx = rand() % (X), ty = rand() % (Y);
double ret = solve(tx, ty);
if (ret > nowdis) {
nowdis = ret;
x = tx; y = ty;
}
}
printf("The safest point is (%.1f, %.1f).\n",
x, y);
}
return 0;
}


  
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