Codeforces 466 B. Wonder Room

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B. Wonder Room

time limit per test
1 second

memory limit per test
256 megabytes

input
standard input

output
standard output

The start of the new academic year brought about the problem of accommodation students into dormitories. One of such dormitories has aa × b square
meter wonder room. The caretaker wants to accommodate exactly n students there. But the law says that there must be at least 6 square meters per student
in a room (that is, the room for n students must have the area of at least 6n square
meters). The caretaker can enlarge any (possibly both) side of the room by an arbitrary positive integer of meters. Help him change the room so as all nstudents
could live in it and the total area of the room was as small as possible.

Input

The first line contains three space-separated integers n, a and b (1 ≤ n, a, b ≤ 109)
— the number of students and the sizes of the room.

Output

Print three integers s, a1 and b1 (a ≤ a1; b ≤ b1) —
the final area of the room and its sizes. If there are multiple optimal solutions, print any of them.

Sample test(s)

input

3 3 5

output

18
3 6

input

2 4 4

output

16
4 4

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>

using namespace std;

typedef long long int LL;

LL n,a,b;

int main()
{
cin>>n>>a>>b;
LL s=n*6;
if(a*b>=s)
{
cout<<a*b<<endl;
cout<<a<<" "<<b<<endl;
return 0;
}
bool flag=false;
if(b<a)
{
swap(a,b);
flag=true;
}

LL X,Y,AREA=(1LL<<62);
int nt=0;
for(LL i=a;i<s;i++)
{
LL j=s/i;
if(j*i<s) j++;
nt++;
if(j<b) break;
if(j*i<AREA)
{
AREA=i*j;
X=i;Y=j;
if(flag) swap(X,Y);
}
else if(j*i==s)
{
cout<<i*j<<endl;
if(flag) swap(i,j);
cout<<i<<" "<<j<<endl;
return 0;
}
else if(j*i>AREA&&nt>20000)
{
break;
}
}
cout<<X*Y<<endl;
cout<<X<<" "<<Y<<endl;

return 0;
}