LeetCode: Reverse Integer
2014-09-09 16:28
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题目
https://oj.leetcode.com/problems/reverse-integer/分析
循环求解即可。代码
class Solution{
public:
int reverse(int x)
{
bool minus = false;
int res = 0;
if (x < 0)
{
x = -x;
minus = true;
}
while (x != 0)
{
int t;
t = x % 10;
x = x / 10;
res = res * 10 + t;
}
if (minus)
res = -res;
return res;
}
};
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