Codeforces Round #265 (Div. 2) 题解
2014-09-08 03:08
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A:给你一个二进制数,问你加一以后改变多少位
解题思路:乱搞
解题代码:
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解题思路:乱搞
解题代码:
// File Name: c.cpp // Author: darkdream // Created Time: 2014年09月07日 星期日 23时55分52秒 #include<vector> #include<list> #include<map> #include<set> #include<deque> #include<stack> #include<bitset> #include<algorithm> #include<functional> #include<numeric> #include<utility> #include<sstream> #include<iostream> #include<iomanip> #include<cstdio> #include<cmath> #include<cstdlib> #include<cstring> #include<ctime> #define LL long long using namespace std; int a[1005]; int b[1005]; char str[1005]; int main(){ int n , p ; scanf("%d %d",&n,&p); scanf("%s",&str[1]); memset(a,0,sizeof(a)); memset(b,0,sizeof(b)); for(int i = 1;i <= n;i ++) { a[i] = str[i] - 'a' + 1; } int ans = 0 ; //for(int i =1 ;i <= n;i++) // printf("%d ",a[i]); for(int i = n;i >= 1 ;i --) { int j ; int s; for(s = a[i] + 1 ; s <= p ;s ++) { if(s != a[i-1] &&( i-2 == -1 || (s != a[i-2]) )) { b[i] = s; b[i-1] = a[i-1]; break; } } if(s == p + 1) continue; //printf("\n%d %d\n",i,s); for( j = i+1;j<= n;j ++) { for( s = 1; s <= p;s ++) { if(s != b[j-1] && s!= b[j-2]) { b[j] = s; //printf("%d***\n",s); break; } } if(s == p + 1) { break; } } if(j == n+1) { ans = i; break; } } if(!ans) { printf("NO\n"); return 0 ; } for(int i = 1;i <= ans -1;i ++) printf("%c",a[i] + 'a' -1 ); for(int j = ans ;j <= n;j ++) printf("%c",b[j] + 'a' -1); return 0; }
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