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uva 1076 - Password Suspects(AC自动机+记忆化搜索)

2014-09-05 22:29 393 查看
题目链接:uva 1076 - Password Suspects

题目大意:有一个长度为n的密码,存在m个子串,问说有多少种字符串满足,如果满足个数不大于42,按照字典序输出。

解题思路:根据子串构建AC自动机,然后记忆化搜索,dp[i][u][s]表示第i个字符,在u节点,匹配s个子串。
#include <cstdio>
#include <cstring>
#include <queue>
#include <string>
#include <vector>
#include <iostream>
#include <algorithm>

using namespace std;

typedef long long ll;

const int maxn = 105;
const int maxs = (1<<10)+5;
const int sigma_size = 26;

struct Aho_Corasick {
int sz, g[maxn][sigma_size];
int val[maxn], fail[maxn];

void init();
int idx(char ch);
void insert(char* str, int k);
void get_fail();
}AC;

int N, M;
vector<string> vec;
ll dp[30][maxn][maxs];

void init () {
AC.init();
char str[20];

for (int i = 0; i < M; i++) {
cin >> str;
AC.insert(str, i);
}
AC.get_fail();
memset(dp, -1, sizeof(dp));
}

ll solve (int d, int u, int s) {

if (d >= N)
return s == (1<<M)-1 ? 1 : 0;

if (dp[d][u][s] != -1)
return dp[d][u][s];

ll& ret = dp[d][u][s];
ret = 0;

for (int i = 0; i < sigma_size; i++) {
int v = AC.g[u][i];
ret += solve(d + 1, v, s | AC.val[v]);
}
return ret;
}

void search (int d, int u, int s, string str) {

if (d >= N) {
if (s == (1<<M) - 1)
vec.push_back(str);
return;
}

if (dp[d][u][s] <= 0)
return ;

for (int i = 0; i < sigma_size; i++) {
int v = AC.g[u][i];
char ch = 'a' + i;
search(d + 1, v, s | AC.val[v], str + ch);
}
}

int main () {
int cas = 0;
while (scanf("%d%d", &N, &M) == 2 && N + M) {
init();
ll ans = solve(0, 0, 0);
//printf("Case %d: %lld suspects\n", ++cas, ans);
cout << "Case " << ++cas << ": " << ans << " suspects" << endl;

if (ans <= 42) {
vec.clear();
search(0, 0, 0, "");
sort(vec.begin(), vec.end());
for (int i = 0; i < vec.size(); i++)
cout << vec[i] << endl;
}
}
return 0;
}

void Aho_Corasick::init() {
sz = 1;
memset(g[0], 0, sizeof(g[0]));
}

int Aho_Corasick::idx(char ch) {
return ch - 'a';
}

void Aho_Corasick::insert(char* str, int k) {
int u = 0, n = strlen(str);

for (int i = 0; i < n; i++) {
int v = idx(str[i]);
if (g[u][v] == 0) {
val[sz] = 0;
memset(g[sz], 0, sizeof(g[sz]));
g[u][v] = sz++;
}
u = g[u][v];
}
val[u] |= (1<<k);
}

void Aho_Corasick::get_fail() {
queue<int> que;

for (int i  = 0; i < sigma_size; i++) {
int u = g[0][i];
if (u) {
fail[u] = 0;
que.push(u);
}
}

while (!que.empty()) {
int r = que.front();
que.pop();

for (int i = 0; i < sigma_size; i++) {
int u = g[r][i];

if (u == 0) {
g[r][i] = g[fail[r]][i];
continue;
}

que.push(u);
int v = fail[r];
while (v && g[v][i] == 0)
v = fail[v];

fail[u] = g[v][i];
val[u] |= val[fail[u]];
}
}
}
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