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UVA 12083 - Guardian of Decency(二分图最大匹配)

2014-09-03 23:08 363 查看


UVA 12083 - Guardian of Decency

题目链接

题意:给定一些男女,满足身高差不大于40,喜欢同一种音乐,不喜欢同一种体育项目,并且性别不同,就可能发生关系,现在老师要带一些男女出去玩,要求不能有一对发生关系,问最多能带多少人

思路:分男女,把会发生关系的连边,然后做最大匹配,最后n-最大匹配就是最多能带的人

代码:

#include <cstdio>
#include <cstring>
#include <string>
#include <vector>
#include <iostream>
#include <cstdlib>
using namespace std;

const int N = 505;

struct People {
int h;
string music, sport;
People() {}
People(int h, string music, string sport) {
this->h = h;
this->music = music;
this->sport = sport;
}
}boy
, girl
;

vector<int> g
;

int bn, gn;

int T, n;

bool judge(People a, People b) {
if (abs(a.h - b.h) <= 40 && a.music == b.music && a.sport != b.sport) return true;
return false;
}

int match
, vis
;

bool dfs(int u) {
for (int i = 0; i < g[u].size(); i++) {
int v = g[u][i];
if (vis[v]) continue;
vis[v] = 1;
if (match[v] == -1 || dfs(match[v])) {
match[v] = u;
return true;
}
}
return false;
}

int hungary() {
int ans = 0;
memset(match, -1, sizeof(match));
for (int i = 0; i < bn; i++) {
memset(vis, 0, sizeof(vis));
if (dfs(i)) ans++;
}
return ans;
}

int main() {
cin >> T;
while (T--) {
cin >> n;
int h; bn = gn = 0;
string sex, music, sport;
for (int i = 0; i < n; i++) {
cin >> h >> sex >> music >> sport;
if (sex == "M") boy[bn++] = People(h, music, sport);
else girl[gn++] = People(h, music, sport);
}
for (int i = 0; i < bn; i++) {
g[i].clear();
for (int j = 0; j < gn; j++) {
if (judge(boy[i], girl[j]))
g[i].push_back(j);
}
}
printf("%d\n", n - hungary());
}
return 0;
}
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