POJ 2028 When Can We Meet? (又是一道水题)
2014-09-02 19:11
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【题目简述】:N代表有几个会员,Q代表有几个会员的时候开会才算做有效,接下来N行,每行第一个数字代表这行有M个数,说明这个会员在哪几天有时间。最后让我们求出 最快 哪天开会。
【分析】:简单题,见代码。
【分析】:简单题,见代码。
// 248K 47Ms #include<iostream> using namespace std; int M[101]; int N,Q; int main() { int m; int m1; while(1) { cin>>N>>Q; if(N == 0&&Q == 0 ) break; memset(M,0,sizeof(M)); while(N--) { cin>>m; for(int i =0;i<m;i++) { cin>>m1; M[m1]++; } } int Max = 0; int a; for(int j = 0;j<=100;j++) { if(M[j]>Max){ Max = M[j]; a = j; } } if(Max>=Q) cout<<a<<endl; else cout<<"0"<<endl; } return 0; }
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