ZOJ-3607
2014-08-25 12:01
155 查看
其实是一道水题,枚举一下就OK了,注意售货员睡着以后就不会醒来了,所以后面的东西都卖不了了
#include<cstdio> #include<set> #include<vector> using namespace std; int main() { int T, n, p, t; scanf("%d", &T); vector<int> V1, V2; set<int> S; while (T--) { scanf("%d", &n); V1.clear(); V2.clear(); S.clear(); for (int i = 0; i < n; i++) { scanf("%d", &p); V1.push_back(p); } int prev = 0; for (int i = 0; i < n; i++) { scanf("%d", &t); V2.push_back(t); S.insert(t - prev); prev = t; } double ww, res = 0; for (set<int>::iterator it = S.begin(); it != S.end(); it++) { int w = *it, sum = 0, total = 0; prev = 0; for (size_t i = 0; i < V2.size(); i++) if (V2[i] - prev <= w) { sum += V1[i]; total++; prev = V2[i]; } else break; double aver = total ? sum * 1.0 / total : 0; if (aver > res) { res = aver; ww = w; } } printf("%.6lf %.6lf\n", ww, res); } return 0; }
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