[LeetCode] Validate Binary Search Tree
2014-08-23 15:33
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Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
这题和上题基本一样,中序遍历解决/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isValidBST(TreeNode root) {
if (root == null) {
return true;
}
List<TreeNode> pre = new ArrayList<TreeNode>();
return helper(root, pre);
}
private boolean helper(TreeNode root, List<TreeNode> pre) {
if (root == null) {
return true;
}
boolean left = helper(root.left, pre);
if (pre.size() > 0 && pre.get(0).val >= root.val) {
return false;
}
if (pre.size() < 1) {
pre.add(root);
} else {
pre.set(0, root);
}
boolean right = helper(root.right, pre);
return left && right;
}
}
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
这题和上题基本一样,中序遍历解决/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isValidBST(TreeNode root) {
if (root == null) {
return true;
}
List<TreeNode> pre = new ArrayList<TreeNode>();
return helper(root, pre);
}
private boolean helper(TreeNode root, List<TreeNode> pre) {
if (root == null) {
return true;
}
boolean left = helper(root.left, pre);
if (pre.size() > 0 && pre.get(0).val >= root.val) {
return false;
}
if (pre.size() < 1) {
pre.add(root);
} else {
pre.set(0, root);
}
boolean right = helper(root.right, pre);
return left && right;
}
}
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