您的位置:首页 > 移动开发 > Android开发

【android】让popupwindow显示在view的上方并与该view水平居中对齐

2014-08-19 23:42 555 查看
首先,废话少说,先上效果图:



代码:

public class MainActivity extends Activity implements OnClickListener{

private Button showBtn1;
private Button showBtn2;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

showBtn1 = (Button) findViewById(R.id.showBtn1);
showBtn2 = (Button) findViewById(R.id.showBtn2);
showBtn1.setOnClickListener(this);
showBtn2.setOnClickListener(this);
}

@Override
public void onClick(View v) {
// TODO Auto-generated method stub
View popupView = LayoutInflater.from(this).inflate(R.layout.popup, null);
PopupWindow popupWindow = new PopupWindow(popupView, ViewGroup.LayoutParams.WRAP_CONTENT,
ViewGroup.LayoutParams.WRAP_CONTENT, true);
popupWindow.setBackgroundDrawable(new BitmapDrawable());
popupView.measure(MeasureSpec.UNSPECIFIED, MeasureSpec.UNSPECIFIED);
int popupWidth = popupView.getMeasuredWidth();
int popupHeight =  popupView.getMeasuredHeight();
int[] location = new int[2];
switch (v.getId()) {
case R.id.showBtn1:
v.getLocationOnScreen(location);
popupWindow.showAtLocation(v, Gravity.NO_GRAVITY, (location[0]+v.getWidth()/2)-popupWidth/2,
location[1]-popupHeight);
break;
case R.id.showBtn2:
v.getLocationOnScreen(location);
popupWindow.showAtLocation(v, Gravity.NO_GRAVITY, (location[0]+v.getWidth()/2)-popupWidth/2,
location[1]-popupHeight);
break;

default:
break;
}
}
}


Demo下载:http://download.csdn.net/detail/u011494050/7787359
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: