UVa 11715 - Car
2014-08-19 19:33
85 查看
题目:有一辆车以初速度u做匀加速直线运动,加速度是a,用 t 时间走了s位移,这时速度是v。
现在已知其中的3搁置,求另外两个。
分析:物理题。s = u*t + 0.5*a*t^2;v = u + a*t;v^2 - u^2 = 2*a*s;利用这三个式子求解即可。
说明:都快忘光了╮(╯▽╰)╭。
现在已知其中的3搁置,求另外两个。
分析:物理题。s = u*t + 0.5*a*t^2;v = u + a*t;v^2 - u^2 = 2*a*s;利用这三个式子求解即可。
说明:都快忘光了╮(╯▽╰)╭。
#include <iostream> #include <cstdlib> #include <cstdio> #include <cmath> using namespace std; double u, v, a, t, s; int main() { int n, T = 1; while ( ~scanf("%d",&n) && n ) { printf("Case %d:",T ++); if (n == 1) { scanf("%lf%lf%lf",&u,&v,&t); a = (v - u) / t; s = u * t + 0.5 * a * t * t; printf(" %.3lf %.3lf\n",s,a); } else if (n == 2) { scanf("%lf%lf%lf",&u,&v,&a); t = (v - u) / a; s = u * t + 0.5 * a * t * t; printf(" %.3lf %.3lf\n",s,t); } else if (n == 3) { scanf("%lf%lf%lf",&u,&a,&s); v = sqrt(u * u + 2 * a * s); t = (v - u) / a; printf(" %.3lf %.3lf\n",v,t); } else if (n == 4) { scanf("%lf%lf%lf",&v,&a,&s); u = sqrt(v * v - 2 * a * s); t = (v - u) / a; printf(" %.3lf %.3lf\n",u,t); } } return 0; }
相关文章推荐
- UVA 11766 Racing Car Computer --DP
- UVA 11766 - Racing Car Computer(DP)
- uva 12661 funning car racing
- UVa 10114 - Loansome Car Buyer
- UVA 12661 Funny Car Racing
- UVALive-6485-Electric Car Rally(BFS)
- UVa10114 - Loansome Car Buyer
- 最短路 uva12661 Funny Car Racing
- UVA 12661 Funny Car Racing
- uva 10457 - Magic Car ( 最小瓶颈树 的应用)
- UVALive 6485 Electric Car Rally (BFS,优先队列)
- uva 11766 - Racing Car Computer(dp)
- BZOJ 1443 [JSOI2009]游戏Game | UVALive 5882 Racing Car Trail
- Rent a Car UVA - 12433
- uva 11766 Racing Car Computer(DP)
- UVALive-6485-Electric Car Rally(BFS)
- UVA 12433 Rent a Car
- UVALive 6485 Electric Car Rally (BFS,PQ)
- UVA 10457 Magic Car——最小瓶颈路
- UVa 10114 Loansome Car Buyer (模拟)