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Quartz,启动不立即执行问题

2014-08-19 14:37 183 查看
我的Quartz 是2.2版本,

在java程序中写了两个加入计划方法

////  添加简单计划任务 author:iresearch.com.cn -- jackical
public static void AddSimplejob(String jobName,String strTrigger,int id,int hour,int minute,Date DateStart) throws SchedulerException{

Scheduler sched=sf.getScheduler();

Calendar calendar=GregorianCalendar.getInstance();
calendar.setTime(DateStart);
int intYear= calendar.get(Calendar.YEAR);
int intMonth=calendar.get(Calendar.MONTH)+1;
int intDay=calendar.get(Calendar.DAY_OF_MONTH);

Date runDate=DateBuilder.dateOf(hour, minute, 0,intDay,intMonth,intYear);   //////  设置执行的时间

JobDetail jobDetail=JobBuilder.newJob(DoJob.class)
.withIdentity(jobName,JOB_GROUP_NAME)
.usingJobData("id",id)
.build();

SimpleTrigger trigger=(SimpleTrigger)TriggerBuilder
.newTrigger()
.withIdentity(strTrigger,TRIGGER_GROUP_NAME)
.startAt(runDate)
.withSchedule(SimpleScheduleBuilder.simpleSchedule()
.withIntervalInMinutes(3)
.withRepeatCount(0)
)
.build();

/*
* 				.withSchedule(SimpleScheduleBuilder.simpleSchedule()
.withIntervalInSeconds(10)
.withRepeatCount(0)
)
* */

sched.scheduleJob(jobDetail,trigger);
sched.start();
}

/////  添加定时任务 author:iresearch.com.cn -- jackical
public static void AddCronJob(String jobName,String strTrigger,int id,String strExp,Date DateStart,Date DateEnd) throws SchedulerException, ParseException{

Scheduler sched=sf.getScheduler();

JobDetail jobDetail=JobBuilder.newJob(DoJob.class)
.withIdentity(jobName,JOB_GROUP_NAME)
.usingJobData("id",id)
.build();

Trigger trigger=(CronTrigger)TriggerBuilder
.newTrigger()
.withIdentity(strTrigger,TRIGGER_GROUP_NAME)
.startAt(DateStart)
.endAt(DateEnd)
.withSchedule(CronScheduleBuilder.cronSchedule(strExp)
.withMisfireHandlingInstructionDoNothing()
)
.build();

sched.scheduleJob(jobDetail,trigger);
sched.start();

}


  

发现这个使用simpleTrigger 的没有参数设置第一次启动时不执行 ....只有CromTrigger 有个参数可以设置第一次添加不执行计划 “withMisfireHandlingInstructionDoNothing()”

转载请注时出处:http://www.cnblogs.com/jackicalSong/

所以我的第一个方法就废了,但第二个方法一样可以用.....
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