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Populating Next Right Pointers in Each Node

2014-08-17 20:16 148 查看
Populating Next Right Pointers in Each Node

Given a binary tree
struct TreeLinkNode {
TreeLinkNode *left;
TreeLinkNode *right;
TreeLinkNode *next;
}


Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to 
NULL
.

Initially, all next pointers are set to 
NULL
.

Note:
You may only use constant extra space.
You may assume that it is a perfect binary tree (ie, all leaves are at the same level, and every parent has two children).

For example,

Given the following perfect binary tree,

1
/  \
2    3
/ \  / \
4  5  6  7


After calling your function, the tree should look like:

1 -> NULL
/  \
2 -> 3 -> NULL
/ \  / \
4->5->6->7 -> NULL

void connect(TreeLinkNode *root) {
if(root==NULL||root->left ==NULL)
return;
else
{
root->left->next =root->right;
}

if(root->next)
{
root->right->next =root->next->left;
}
connect(root->left);
connect(root->right);
}
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标签:  Leetcode