LeetCode——Length of Last Word
2014-08-16 12:30
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Given a string s consists of upper/lower-case alphabets and empty space characters
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
return
中文:给定一个字符串,包括大写/小写字母和空格字符,返回字符串中最后一个单词的长度。
假设最后一个单词不存在,返回0.
注意:一个单词被定义为仅包括非空字符的字符序列。
比如:
给定 s="Hello World",
返回 5.
此题可能是leetcode上面的最简单的一道题了。
Java:
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
"Hello World",
return
5.
中文:给定一个字符串,包括大写/小写字母和空格字符,返回字符串中最后一个单词的长度。
假设最后一个单词不存在,返回0.
注意:一个单词被定义为仅包括非空字符的字符序列。
比如:
给定 s="Hello World",
返回 5.
此题可能是leetcode上面的最简单的一道题了。
Java:
public int lengthOfLastWord(String s) { if(s.trim().equals("")) return 0; String[] str = s.split("\\s+"); int len = str.length; return str[len-1].length(); }
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