您的位置:首页 > 编程语言 > C语言/C++

[C++] 几行代码生成漂亮图片,数学家就是牛!

2014-08-15 23:41 387 查看
信息获得处:http://news.cnblogs.com/n/501488/

分形:http://baike.baidu.com/subview/83243/11213590.htm?fr=aladdin













代码:[采用宏定义的来选择绘制不同的图,所以把最后两个给注释掉了,因为宏冲突,想自己试试可以单独编译运行]

PS:生成的图片是ppm格式的要用格式工厂之类的软件进行转换,也可以自己在程序里直接把图片生成bmp或者其他格式的~

// NOTE: compile with g++ filename.cpp -std=c++11
#include <iostream>
#include <cmath>
#include <cstdlib>
#define DIM 1024
#define DM1 (DIM-1)
#define _sq(x) ((x)*(x)) // square
#define _cb(x) abs((x)*(x)*(x)) // absolute value of cube
#define _cr(x) (unsigned char)(pow ((x),1.0/3.0)) // cube root
#define F

unsigned char GR (int,int);
unsigned char BL (int,int);

unsigned char RD (int i,int j){
#ifdef A
return (char)(_sq(cos(atan2(j-512,i-512)/2))*255);
#endif

#ifdef B
#define r(n) (rand ()%n)
static char c[1024][1024];
return!c[i][j]?c[i][j]=!r(999)?r(256):RD ((i+r(2))%1024,(j+r(2))%1024):c[i][j];
#endif

#ifdef C
float x=0,y=0;
int k;
for(k=0;k++<256;){
float a=x*x-y*y+ (i-768.0)/512;
y=2*x*y+ (j-512.0)/512;
x=a;
if(x*x+y*y>4)break;
}
return log (k)*47;
#endif

#ifdef D
double a=0,b=0,c,d,n=0;
while((c=a*a)+(d=b*b)<4&&n++<880){
b=2*a*b+j*8e-9-.645411;
a=c-d+i*8e-9+.356888;
}
return 255*pow ((n-80)/800,3.);
#endif

#ifdef E
static double k;
k+=rand ()/1./RAND_MAX;
int l=k;
l%=512;
return l>255?511-l:l;
#endif

#ifdef F
float s=3./(j+99);
float y=(j+sin ((i*i+_sq (j-700)*5)/100./DIM)*35)*s;
return (int((i+DIM)*s+y)%2+int((DIM*2-i)*s+y)%2)*127;
#endif
/*
#ifdef G
#define D DIM
#define M m[(x+D+ (d==0)-(d==2))%D][(y+D+ (d==1)-(d==3))%D]
#define R rand ()%D
#define B m[x][y]
return(i+j)?256-(BL (i,j))/2:0;
#endif
*/
/*
#ifdef H
#define A float a=0,b,k,r,x
#define B int e,o
#define C (x) x>255?255:x
#define R return #define D DIM
R BL (i,j)*(D-i)/D;
#endif
*/
return 0;
}
unsigned char GR (int i,int j){
#ifdef A
return (char)(_sq (cos (atan2(j-512,i-512)/2-2*acos (-1)/3))*255);
#endif

#ifdef B
static char c[1024][1024];
return!c[i][j]?c[i][j]=!r(999)?r(256):GR ((i+r(2))%1024,(j+r(2))%1024):c[i][j];
#endif

#ifdef C
float x=0,y=0;
int k;
for(k=0;k++<256;){
float a=x*x-y*y+ (i-768.0)/512;
y=2*x*y+ (j-512.0)/512;
x=a;
if(x*x+y*y>4)break;
}
return log (k)*47;
#endif

#ifdef D
double a=0,b=0,c,d,n=0;
while((c=a*a)+(d=b*b)<4&&n++<880){
b=2*a*b+j*8e-9-.645411;
a=c-d+i*8e-9+.356888;
}
return 255*pow ((n-80)/800,.7);
#endif

#ifdef E
static double k;
k+=rand ()/1./RAND_MAX;
int l=k;
l%=512;
return l>255?511-l:l;
#endif

#ifdef F
float s=3./(j+99);
float y=(j+sin ((i*i+_sq (j-700)*5)/100./DIM)*35)*s;
return (int(5*((i+DIM)*s+y))%2+int(5*((DIM*2-i)*s+y))%2)*127;
#endif
/*
#ifdef G
#define A
static int m[D][D],e,x,y,d,c[4],f,n;
if (i+j<1){
for (d=D*D;d;d--){
m[d%D][d/D]=d%6?0:rand ()%2000?1:255;
}
for (n=1 return RD (i,j);
#endif
*/
/*
#ifdef H
#define E DM1
#define F static float
#define G for (
#define H r=a*1.6/D+2.4;x=1.0001*b/D
R BL (i,j)*(D-j/2)/D;
#endif
*/
return 0;
}
unsigned char BL (int i,int j){
#ifdef A
return (char)(_sq (cos (atan2(j-512,i-512)/2+2*acos (-1)/3))*255);
#endif

#ifdef B
static char c[1024][1024];
return!c[i][j]?c[i][j]=!r(999)?r(256):BL((i+r(2))%1024,(j+r(2))%1024):c[i][j];
#endif

#ifdef C
float x=0,y=0;
int k;
for(k=0;k++<256;){
float a=x*x-y*y+ (i-768.0)/512;
y=2*x*y+ (j-512.0)/512;
x=a;
if(x*x+y*y>4)break;
}
return 128-log (k)*23;
#endif

#ifdef D
double a=0,b=0,c,d,n=0;
while((c=a*a)+(d=b*b)<4&&n++<880){
b=2*a*b+j*8e-9-.645411;
a=c-d+i*8e-9+.356888;
}
return 255*pow ((n-80)/800,.5);
#endif

#ifdef E
static double k;
k+=rand ()/1./RAND_MAX;
int l=k;
l%=512;
return l>255?511-l:l;
#endif

#ifdef F
float s=3./(j+99);
float y=(j+sin ((i*i+_sq (j-700)*5)/100./DIM)*35)*s;
return (int(29*((i+DIM)*s+y))%2+int(29*((DIM*2-i)*s+y))%2)*127;
#endif
/*
#ifdef G
A;n;n++){
x=R;y=R;
if(B==1){
f=1;
for(d=0;d<4;d++){
c[d]=M;
f=f<c[d]?c[d]:f;
}
if(f>2){B=f-1;}
else{
++e%=4;
d=e;
if(!c[e]){
B=0;M=1;
}}}}}
return m[i][j];
#endif
*/
/*
#ifdef H
F c[D][D];
if(i+j<1){A;B;G;a<D;a+=0.1){G b=0;b<D;b++){H;G k=0;k<D;k++){x=r*x*(1-x);
if(k>D/2){e=a;o=(E*x);c[e][o]+=0.01;}}}}}
R C (c[j][i])*i/D;
#endif
*/

return 0;
}

void pixel_write (int,int);
FILE *fp;
int main (){
fp = fopen ("MathPic.ppm","wb");
fprintf (fp, "P6\n%d %d\n255\n", DIM, DIM);
for(int j=0;j<DIM;j++)
for(int i=0;i<DIM;i++)
pixel_write (i,j);
fclose (fp);
return 0;
}
void pixel_write (int i, int j){
static unsigned char color[3];
color[0] = RD (i,j)&255;
color[1] = GR (i,j)&255;
color[2] = BL (i,j)&255;
fwrite (color, 1, 3, fp);
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: