Codeforces Round #249 (Div. 2) —— B

B. Pasha Maximizes

time limit per test
1 second

memory limit per test
256 megabytes

input
standard input

output
standard output

Pasha has a positive integer a without
leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits of the integer.
Help Pasha count the maximum number he can get if he has the time to make at most k swaps.

Input
The single line contains two integers a and k (1 ≤ a ≤ 1018; 0 ≤ k ≤ 100).

Output
Print the maximum number that Pasha can get if he makes at most k swaps.

Sample test(s)

input

1990 1

output

9190

input

300 0

output

300

input

1034 2

output

3104

input

9090000078001234 6

output

9907000008001234



题意：用k次只交换相邻的数字使得新的数字尽量大。

这题似乎不难，但我做了很久，还看过别人的代码 ==。

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int k, i, j;
    char a[20];

    while(~scanf("%s%d", a,&k))
    {
        int len = strlen(a);
        for(i=0; i<len; i++)
        {
            int index = i;
            for(j=i+1; j<len && j<=i+k; j++)
            {
                if(a[j] > a[index])
                    index = j;
            }
            if(index != i)
                for(j=index; j>i; j--)
                    swap(a[j],a[j-1]), k--;
        }
        printf("%s\n", a);
    }
    return 0;
}