poj 1426 Find The Multiple(bfs)
2014-08-09 10:58
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Find The Multiple
Description
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing
no more than 100 decimal digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them
is acceptable.
Sample Input
Sample Output
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Time Limit: 1000MS | Memory Limit: 10000K | |||
Total Submissions: 18023 | Accepted: 7303 | Special Judge |
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing
no more than 100 decimal digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them
is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
#include<cstdio> #include<cmath> #include<cstring> #include<iostream> #include<queue> #define N 50 using namespace std; unsigned long long ans; int dfs(unsigned long long a,unsigned long long b,int n ) { if(a>=b) return 0; if(b%n==0) { ans = b;return 1; } if(dfs(b,b*10,n)) return 1; return dfs(b,b*10+1,n); } int main() { int n; while(cin >> n&&n) { if(dfs(0,1,n)) cout << ans << endl; } return 0; }
[/code]
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