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poj 2239 二分 最大匹配

2014-08-04 12:57 337 查看
题意:给出n个课程每周的课程安排,求最多可以上几个课。

解法:二分匹配-最大匹配

左集合,课程

右集合:课程上课时间的排序集合

/*
----------------------------------

Love is more than a word.
It says so much.
When I see these four letters,
I almost feel your touch.
This is only happened since
I fell in love with you.
Why this word does this,
I haven't got a clue.

To My Goddess
CY
----------------------------------
*/

#include<iostream>
#include<cstring>
#include<algorithm>
#include<cstdlib>
#include<vector>
#include<cmath>
#include<stdlib.h>
#include<iomanip>
#include<list>
#include<deque>
#include<map>
#include <stdio.h>
#include <queue>

#define maxn 350+5

#define ull unsigned long long
#define ll long long
#define reP(i,n) for(i=1;i<=n;i++)
#define REP(i,a,b) for(i=a;i<=b;i++)
#define rep(i,n) for(i=0;i<n;i++)

#define cle(a) memset(a,0,sizeof(a))
#define clehead(a) rep(i,maxn)a[i]=-1

/*
The time of story :
**  while(1)
{
once upon a time,
there was a mountain,
on top of which there was a temple,
in which there was an old monk and a little monk.
Old monk was telling stories inside the temple.
What was he talking about?
**  }

ÎûÎû
(*^__^*)
*/

#define sci(a) scanf("%d",&a)
#define scd(a) scanf("%lf",&a)
#define pri(a) printf("%d",a)
#define prie(a) printf("%d\n",a)
#define prd(a)  printf("%lf",a)
#define prde(a) printf("%lf\n",a)
#define pre printf("\n")

#define LL(x) x<<1
#define RR(x) x<<|1

#define pb push_back
#define mod 90001
#define PI 3.141592657

const ull INF = 1LL << 61;
const int inf =   int(1e5)+10;
const double eps=1e-5;

using namespace std;

struct node
{
int u,v,w;
int next;
};

bool cmp(int a,int b){
return a>b;
}
int n,t;
vector<int>V[350];
bool bmap[maxn][maxn];
bool bmark[10000];
int nx,ny;
int cx[10000];
int cy[10000];

int findpath(int u)
{
int i,j,k;
rep(i,ny){
if(bmap[u][i]&&!bmark[i]){
bmark[i]=1;
if(cy[i]==-1||findpath(cy[i]))
{
cy[i]=u;
cx[u]=i;
return 1;
}
}
}
return 0;
}

int maxmatch()
{
int i,j,k;
int res(0);
rep(i,nx)cx[i]=-1;
rep(j,ny)cy[j]=-1;
rep(i,nx){
if(cx[i]==-1){
rep(j,ny)bmark[j]=0;
res+=findpath(i);
}
}
return res;
}
int main()
{
//  freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
while(cin>>n)
{
int i,j,k;
cle(bmap);
int used[20][20];
cle(used);
int t;
rep(i,n)
{
V[i].clear();
sci(t);
V[i].pb(t);
rep(j,t)
{
int x,y;
cin>>x>>y;
V[i].pb(x);
V[i].pb(y);
used[x][y]=1;
}
}
int ip=0;
ny=0;
nx=n;
reP(i,7){
reP(j,12){
if(used[i][j]){
used[i][j]=ip++;
}
}
}
ny=ip;
rep(i,n)
{
for(j=1;j<=2*V[i][0];j+=2)
{
bmap[i][used[V[i][j]][V[i][j+1]]]=true;
}
}
cout<<maxmatch()<<endl;
}
return 0;
}
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