UVA10650 - Determinate Prime - 数论
2014-08-02 15:55
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#include<stdio.h> #include<string.h> int visit[32005]; int mark[32005]; int a[32005]; void pr() { int i,j; memset(visit,0,sizeof(visit)); int num=0; for(i=2;i<=32004;i++) { if(visit[i]==0) { num++; a[num]=i; } for(j=1;((j<=num)&&(i*a[j]<=32004));j++) { visit[i*a[j]]=1; if(i%a[j]==0) { break; } } } } int main() { int m,n; pr(); int i,j; int flag; while(scanf("%d%d",&n,&m)!=EOF) { int time=0; if(n==0&&m==0) { break; } if(n>m) { int t; t=n; n=m; m=t; } memset(mark,0,sizeof(mark)); for(i=0;a[i+2]<=m;i++) { flag=0; if(a[i]<n) { continue; } for(j=0;a[j]<=m;j++) { if(a[i+j+1]>m||a[i+j+2]>m) { break; } if((a[i+j+1]-a[i+j])==(a[i+j+2]-a[i+j+1])) { if(a[i+j+3]-a[i+j+2]==a[i+j+2]-a[i+j+1]&&(a[i+j+3]>m)) { break; } if(a[i+j+2]-a[i+j+1]==a[i+j]-a[i+j-1]&&(a[i+j-1]<n)) { break; } if(mark[i+j]==0&&j==0) { printf("%d",a[i+j]); flag=1; } else if(mark[i+j]==0) { printf(" %d",a[i+j]); } if(mark[i+j]==1&&(a[i+j+1]-a[i+j])!=(a[i+j]-a[i+j-1])) { printf("%d",a[i+j]); flag=1; } if(mark[i+j+1]==0) { printf(" %d",a[i+j+1]); } if(mark[i+j+2]==0) { printf(" %d",a[i+j+2]); } mark[i+j]=mark[i+j+1]=mark[i+j+2]=1; } else { break; } } if(flag==1) { puts(""); } } } }
这道题坑比较多,重点是4个数字的时候,第一个数超限就不输出后三个,同理,最后一个数超限不输出前三个
比如
251 269的时候输出4个
那么252 269不输出
251 268也不输出
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