uva133(The Dole Queue)—线性表
2014-08-02 08:23
387 查看
The Dole Queue |
inwards. Someone is arbitrarily chosen as number 1, and the rest are numbered counter-clockwise up to N (who will be standing on 1's left). Starting from 1 and moving counter-clockwise, one labour official counts off k applicants, while another official starts
from N and moves clockwise, counting m applicants. The two who are chosen are then sent off for retraining; if both officials pick the same person she (he) is sent off to become a politician. Each official then starts counting again at the next available person
and the process continues until no-one is left. Note that the two victims (sorry, trainees) leave the ring simultaneously, so it is possible for one official to count a person already selected by the other official.
Input
Write a program that will successively read in (in that order) the three numbers (N, k and m; k, m > 0, 0 < N < 20) and determine the order in which the applicants are sent off for retraining. Each set of threenumbers will be on a separate line and the end of data will be signalled by three zeroes (0 0 0).
Output
For each triplet, output a single line of numbers specifying the order in which people are chosen. Each number should be in a field of 3 characters. For pairs of numbers list the person chosen by the counter-clockwiseofficial first. Separate successive pairs (or singletons) by commas (but there should not be a trailing comma).
Sample input
10 4 3 0 0 0
Sample output
4
8,
9
5,
3
1,
2
6,
10,
7
where
represents a space.
#include<stdio.h> #include<string.h> #define MAX 100 int sqlist[MAX]; int mark[MAX]; void init(int n){ int i; for(i=0;i<n;i++){ sqlist[i]=i; } memset(mark,0,sizeof(mark)); } int do_select(int n,int k,int m,int& right,int& left){ int countr=0,countl=0; while(countr<k){ right=(right+1)%n; if(mark[right]==0){ countr++; } } while(countl<m){ left=(left-1+n)%n; if(mark[left]==0){ countl++; } } mark[right]=mark[left]=1; if(right!=left) return 2; else return 1; } int main(){ int n,k,m; while(scanf("%d%d%d",&n,&k,&m)!=EOF){ if(n==0&&k==0&&m==0) break; init(n); int temp=n; int clo=n,coclo=-1; while(n!=0){ if(do_select(temp,k,m,coclo,clo)==2){ printf("%3d%3d",sqlist[coclo]+1,sqlist[clo]+1); n=n-2; } else{ printf("%3d",sqlist[coclo]+1); n=n-1; } if(n!=0){ printf(","); } } printf("\n"); } return 0; }
The Dole Queue |
inwards. Someone is arbitrarily chosen as number 1, and the rest are numbered counter-clockwise up to N (who will be standing on 1's left). Starting from 1 and moving counter-clockwise, one labour official counts off k applicants, while another official starts
from N and moves clockwise, counting m applicants. The two who are chosen are then sent off for retraining; if both officials pick the same person she (he) is sent off to become a politician. Each official then starts counting again at the next available person
and the process continues until no-one is left. Note that the two victims (sorry, trainees) leave the ring simultaneously, so it is possible for one official to count a person already selected by the other official.
Input
Write a program that will successively read in (in that order) the three numbers (N, k and m; k, m > 0, 0 < N < 20) and determine the order in which the applicants are sent off for retraining. Each set of threenumbers will be on a separate line and the end of data will be signalled by three zeroes (0 0 0).
Output
For each triplet, output a single line of numbers specifying the order in which people are chosen. Each number should be in a field of 3 characters. For pairs of numbers list the person chosen by the counter-clockwiseofficial first. Separate successive pairs (or singletons) by commas (but there should not be a trailing comma).
Sample input
10 4 3 0 0 0
Sample output
4
8,
9
5,
3
1,
2
6,
10,
7
where
represents a space.
相关文章推荐
- UVa 133 - The Dole Queue
- uva 133 The Dole Queue 双向约瑟夫环 模拟实现
- UVa 133 - The Dole Queue
- UVA 133 The Dole Queue
- 算法竞赛入门经典(紫书)第四章—— The Dole Queue UVA-133
- Uva 133 - The Dole Queue//模拟,链表
- 【模拟】【环形数组】-UVA-133- The Dole Queue |java实现
- UVA 133 The Dole Queue
- 水题:UVa133-The Dole Queue
- 算法竞赛入门经典第四章例题4-3 The Dole Queue UVA - 133
- 紫书章四例题3——UVA 133 TheDole Queue
- The Dole Queue UVA133
- UVA 133 The Dole Queue 约瑟夫问题的变种,手写链表,模拟
- uva 133 - The Dole Queue
- UVA - 133 The Dole Queue
- Uva 133 - The Dole Queue
- 紫书章四例题3——UVA 133 TheDole Queue
- UVA-133 The Dole Queue
- 假期训练——The Dole Queue UVA - 133 模拟
- UVa133 - The Dole Queue