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[leetcode]Symmetric Tree

2014-07-31 19:53 369 查看
Symmetric Tree


Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).

For example, this binary tree is symmetric:

1
/ \
2   2
/ \ / \
3  4 4  3


But the following is not:

1
/ \
2   2
\   \
3    3


Note:
Bonus points if you could solve it both recursively and iteratively.


算法思路:

思路:递归。镜像判断。

代码如下:

public class Solution {
public boolean isSymmetric(TreeNode root) {
if(root == null || (root.left == null && root.right == null)) return true;
return isSym(root.left, root.right);

}
public boolean isSym(TreeNode left,TreeNode right){
if(left == null && right == null) return true;
if((left == null && right != null) || (left != null && right == null) || right.val != left.val)
         return false;
return isSym(left.left, right.right) && isSym(left.right, right.left);
}
}
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