LeetCode: Convert Sorted List to Binary Search Tree
2014-07-31 10:41
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思路:设计一个找到链表中位数位置的函数,然后以该位置为分界位置,左右递归求解,注意,找到中位数位置后,需要将左边链表与该位置断开,否则会出现死循环。
code:
code:
class Solution { public: ListNode *findMidNode(ListNode *head){ ListNode * p = head, *q; if(p->next == NULL) return p; q = p; while(q != NULL && q->next != NULL){ p = p->next; q = q->next->next; } return p; } TreeNode *sortedListToBST(ListNode *head) { if(head == NULL)return NULL; ListNode *midNode = findMidNode(head); TreeNode *tNode = new TreeNode(midNode->val); ListNode *p = head; while(p != midNode && p->next != midNode) p = p->next; p->next = NULL; if(p != midNode) tNode->left = sortedListToBST(head); tNode->right = sortedListToBST(midNode->next); return tNode; } };
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