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USACO Section 2.1 Healthy Holsteins

2014-07-24 20:41 435 查看
/*
ID: lucien23
PROG: holstein
LANG: C++
*/

#include <iostream>
#include <fstream>
#include <vector>
using namespace std;

bool compFun(int x, int y)
{
int temp, i = 0;

while (true)
{
temp = 1 << i;
if (temp&x > temp&y)
{
return true;
} else if (temp&x < temp&y)
{
return false;
}
i++;
}
}

int main()
{
ifstream infile("holstein.in");
ofstream outfile("holstein.out");
if(!infile || !outfile)
{
cout << "file operation failure!" << endl;
return -1;
}

int arrCnt[15] = {1,3,7,15,31,63,127,255,511,1023,2047,4095,8191,16383,32767};

int V;
infile >> V;
int *minRequire = new int[V];
for (int i=0; i<V; i++)
{
infile >> minRequire[i];
}
int G;
infile >> G;
int **feeds = new int *[G];
for (int i=0; i<G; i++)
{
feeds[i] = new int[V];
for (int j=0; j<V; j++)
{
infile >> feeds[i][j];
}
}

int minScoopsCnt = 16;
int minScoops = 0;

int *sumVita = new int[V];
int sumScoops;
for (int i=1; i<=arrCnt[G-1]; i++)
{//穷举遍历每一种方案
for (int k=0; k<V; k++)
{
sumVita[k] = 0;
}
sumScoops = 0;

for (int j=0; j<G; j++)
{//判断此方案中是否包含饲养类型j(利用移位运算)
int temp = 1 << j;
if ((temp & i) == temp)
{//包含类型j
for (int k=0; k<V; k++)
{
sumVita[k] += feeds[j][k];
}
sumScoops++;
}
}

int k;
for (k=0; k<V; k++)
{
if (sumVita[k] < minRequire[k])
break;
}
if (k==V && (sumScoops<minScoopsCnt || (sumScoops==minScoops && compFun(minScoops, i))))
{
minScoopsCnt = sumScoops;
minScoops = i;
}
}

outfile << minScoopsCnt;
for (int j=0; j<G; j++)
{
int temp = 1 << j;
if ((temp & minScoops) == temp)
{
outfile << " " << j+1;
}
}
outfile << endl;

return 0;
}
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