HDOJ 2008 数值统计

数值统计

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 53403 Accepted Submission(s): 27342



Problem Description

统计给定的n个数中，负数、零和正数的个数。

Input

输入数据有多组，每组占一行，每行的第一个数是整数n（n<100），表示需要统计的数值的个数，然后是n个实数；如果n=0，则表示输入结束，该行不做处理。

Output

对于每组输入数据，输出一行a,b和c，分别表示给定的数据中负数、零和正数的个数。

Sample Input

6 0 1 2 3 -1 0
5 1 2 3 4 0.5
0

Sample Output

1 2 3
0 0 5

Author

lcy

第一次代码：

#include <stdio.h>
int main ()
{
int n,b,c,d;
int a[100];
while (scanf("%d",&n),n!=0)
{
b=c=d=0;
for (int i=0;i<n;i++)
scanf ("%d",&a[i]);
for (int i=0; i<n; i++)
{
if (a[i]>0)    b++;
else if (a[i]<0)   c++;
else d++;
}
printf ("%d %d %d\n",b,c,d);
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129214	2014-07-22 09:14:29	Output Limit Exceeded	2008	125MS	220K	404 B	C++	Hidden Secret

第二次代码：

#include <stdio.h>
int main ()
{
int a,n,b,c,d;
while (scanf("%d",&n),n!=0)
{
b=c=d=0;
while (n--)
{
scanf ("%d",&a);
if (a>0)    b++;
else if (a<0)   c++;
else d++;
}
printf ("%d %d %d\n",b,c,d);
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129271	2014-07-22 09:19:11	Time Limit Exceeded	2008	1000MS	220K	337 B	C++	Hidden Secret

第三次代码：

#include <stdio.h>
int main ()
{
int n,b,c,d;
double a;
while (scanf("%d",&n),n!=0)
{
b=c=d=0;
while (n--)
{
scanf ("%lf",&a);
if (a>0)    b++;
else if (a<0)   c++;
else d++;
}
printf ("%d %d %d\n",b,c,d);
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129402	2014-07-22 09:27:23	Wrong Answer	2008	15MS	260K	351 B	C++	Hidden Secret

第四次代码：

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int main()
{
int n,i,j,k;
double a;

while(scanf("%d",&n)==1)
{

if(n==0)    break;
else
{
int i=0,j=0,k=0;
for(int l=1; l<=n; l++)
{
scanf("%lf",&a);
if(a<0) i++;
else if(a==0)   j++;
else if(a>0)    k++;
}
printf("%d %d %d\n",i,j,k);
}
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129551	2014-07-22 09:36:02	Accepted	2008	0MS	260K	515 B	C++	Hidden Secret

第五次代码：

#include <stdio.h>
int main ()
{
int i,j,k,n;
double a;
while (scanf ("%d",&n),n!=0)
{
i=j=k=0;
while (n--)
{
scanf("%lf",&a);
if (a>0)    i++;
else if (a==0)  j++;
else    k++;
}
printf ("%d %d %d\n",i,j,k);
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129563	2014-07-22 09:36:36	Wrong Answer	2008	0MS	260K	354 B	C++	Hidden Secret

第六次代码：

#include <stdio.h>
int main ()
{
int i,j,k,n;
double a;
while (1)
{
scanf ("%d",&n);
if(n!=0)
{
i=j=k=0;
while (n--)
{
scanf("%lf",&a);
if (a>0)    i++;
else if (a==0)  j++;
else    k++;
}
printf ("%d %d %d\n",i,j,k);
}
else break;
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129601	2014-07-22 09:38:50	Wrong Answer	2008	0MS	260K	458 B	C++	Hidden Secret

第七次代码：

#include <stdio.h>
int main ()
{
int i,j,k,n;
double a;
while (scanf ("%d",&n)==1)
{
if(n!=0)
{
i=j=k=0;
while (n--)
{
scanf("%lf",&a);
if (a>0)    i++;
else if (a==0)  j++;
else    k++;
}
printf ("%d %d %d\n",i,j,k);
}
else break;
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129801	2014-07-22 09:48:26	Wrong Answer	2008	0MS	260K	449 B	C++	Hidden Secret

第八次代码：

#include <stdio.h>
int main ()
{
int i,j,k,n;
double a;
while (scanf ("%d",&n)==1)
{
if(n!=0)
{
i=j=k=0;
for (int b=0;b<n;b++)
{
scanf("%lf",&a);
if (a>0)    i++;
else if (a==0)  j++;
else    k++;
}
}
else break;
printf ("%d %d %d\n",i,j,k);
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129858	2014-07-22 09:51:32	Wrong Answer	2008	0MS	260K	455 B	C++	Hidden Secret

第九次代码：

#include <iostream>
using namespace std;
int main(){
int m,i;
double n;
while(cin>>m)
{
if(m == 0)
break;
int a = 0, b = 0, c = 0;
for (i = 0; i < m; i++)
{
cin>>n;
if(n < 0)
a++;
else if(n > 0)
c++;
else b++;
}
cout<<a<<" "<<b<<" "<<c<<endl;
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11129937	2014-07-22 09:54:50	Accepted	2008	15MS	312K	490 B	C++	Hidden Secret

第十次代码：

#include <stdio.h>
int main ()
{
int b,c,d,n;
double a;
while (scanf ("%d",&n))
{

b=c=d=0;
if(n==0)    break;
else
{
for (int i=0; i<n; i++)
{
scanf("%lf",&a);
if (a>0)    b++;
else if (a==0)  c++;
else    d++;
}
printf ("%d %d %d\n",b,c,d);
}
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11130002	2014-07-22 09:58:23	Wrong Answer	2008	0MS	260K	459 B	C++	Hidden Secret

第十一次代码：

#include <stdio.h>
int main ()
{
int b,c,d,n;
double a;
while (scanf ("%d",&n))
{

b=c=d=0;
if(n==0)    break;
else
{
for (int i=0; i<n; i++)
{
scanf("%lf",&a);
if (a<0)    b++;
else if (a==0)  c++;
else    d++;
}
printf ("%d %d %d\n",b,c,d);
}
}
return 0;
}

Run ID	Submit Time	Judge Status	Pro.ID	Exe.Time	Exe.Memory	Code Len.	Language	Author
11130113	2014-07-22 10:02:34	Accepted	2008	0MS	260K	459 B	C++	Hidden Secret

总结：
呼~终于过了……各种坑爹问题。首先我没注意到输入数字的类型是double型，其次我在考虑累加器上还是有点问题。感觉这次最大问题是在条件判断的误读上，人家输出是有顺序的，结果我忘了这一点，随便就输出，导致错到最后！！！水题注意细节！！！！