[leetcode] Gray Code
2014-07-19 09:20
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The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
gray code sequence is:
Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
思路:看看n=3时的情况就知道了,000,001,011,010,110,111,101,100,就是在n=2的情况下,前面加0和逆序加1
代码:
class Solution {
public:
vector<int> grayCode(int n) {
vector<int> res;
if(n==0){
res.push_back(0);
return res;
}
vector<int> temp=grayCode(n-1);
res=temp;
int len=temp.size();
for(int i=len-1;i>=0;i--){
res.push_back(temp[i]+pow(2,n-1));
}
return res;
}
};
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
[0,1,3,2]. Its
gray code sequence is:
00 - 0 01 - 1 11 - 3 10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
[0,2,3,1]is also a valid gray code sequence according
to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
思路:看看n=3时的情况就知道了,000,001,011,010,110,111,101,100,就是在n=2的情况下,前面加0和逆序加1
代码:
class Solution {
public:
vector<int> grayCode(int n) {
vector<int> res;
if(n==0){
res.push_back(0);
return res;
}
vector<int> temp=grayCode(n-1);
res=temp;
int len=temp.size();
for(int i=len-1;i>=0;i--){
res.push_back(temp[i]+pow(2,n-1));
}
return res;
}
};
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